16a2 + 40ab + 25b2 combine like terms. 7. (2y – 3)(4y2 + 6y + 9). = 8y3 + 12y2 +

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9(3 x – 4y) = 27 x – 36y 27 x – 36y = 9(3 x – 4y). 12(2 x + 1) .

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SOLUTION: Factor completely: 27x3 – 8y3 Hint: use the “difference of two .

(a+b)(a2-ab+b2) = (2x+3y)(4x2-6xy+9y2) = (2x)3+(3y)3 = 8x3+27y3 . Q 3: Find

27x³ - 8y³ = Notice that both terms are perfect squares. 27x³ = 3x * 3x * 3x .

Sep 24, 2011 . x3 + 8y3 (x3 - 2x2y + 4xy2) + (2x2y - 4xy2 + 8y3) x(x2 - 2xy + 4y2) + 2y(x2 - 2xy +

4) 27x3 - 8y 3. 5) x 3-8. 6) x3 - 64. 7) z3 + 27. 8) 125 + ,3. 9) 27 - 8v3. 10) 64 -

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27x3+54x2-36x-8 27x3-54x2+36x+8, Q 2: Expand (2x-3)3 . 8x3-36x2+54x-27 8x

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8y3 = 8 * y * 3 = 8 * 3 * y = 24y 24y - 27. But I'm certain you left off .

Mar 30, 2009 . Can 8y^3 -27 be factored? . Yes, 8y^3 - 27 = (2y)^3 - 3^3 now use the formula

. constructor public Piece (int type) { switch(type) { case 1: // x = new int[4]; y =

1(243x5)(1) + 5(81x4)(-2y) + 10(27x3)(4y2) + 10(9x2)(-8y3) + 5(3x)(16y4) + 1(1)(-

Solve for 8y-3=13y+17. . Education|No Subcategories|Expert answered|Rating

(8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or . X^3 + 27 = 0 subtract

94. 96. 98. 27n3 125 8 n3 a3b3 1 x3 8y3 1 8x3 8x3 27y3 n3 27 87. 89. 91. 93. 95.

5x+ 2 = 27. 8y 3 = 53. 1y + 3 = 12. 9x+ 6 = 78. 2x + 3 = 5. 6y + 6 = 60. 8x 8 = 24.

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. 4y3 =27x2 2.81 y = xy+y3 A NS y = Cx + C3; 4x3 + 27y 2 = 0 2.82 x(y2−1)=2y .

57. x3 27 60. 64a3 27 63. m3 n3 66. 1 125b3 69. x3y3 64 72. 27x3 8y3 75. a b3

27x3+8y3+z3-18xyz 27x3+8y3+z3-9xyz 27x3+8y3+z3-12xyz, Q 4: Find the

PROBLEM 375 Factor 27x3 - 8y3. | Solution; Note that 27 = 33; thus 27x3 = (33) (

3^ 2t 26. 3t t2 27. 3x + 1 2x - 6 x + 2 x - 3 28. x + 1 x -2 Ax 5x - 10 29. 2x - 2 30. 2x

Step 0a. Write the relevant four equations in four unknowns (three from ∇f = λ∇g

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The 3d power of 3m.2y, is (3m.2y)3, or 27m3.8y3. 209. A compound quantity

. -xy -y or 4ry'2 (2xy'2 - 3y) = 27x2 or 8ry'3 - 12yy'2 = 27x or x (8y3 - 27) = 12;y/2 -

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SOLUTION: Factor completely: 27x3 – 8y3 Must use the “difference of two cubes

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. c)(a2 + &2 + c2+&c-ca+a&), - b taking the place of 6 in formula (1). Example 2.

(i) 2x* -3=x2 Cubing, we get 8^9 - 27 - i8ri(2.ri _ 3) - x6 8x9-27 -36x(5-54r3 = x6

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9x2 + 27 = 9 (x2 + 3). How do you factor 8y cubed plus 27? Not sure which .

4a2 12ab 9b2 (2a)2 2(2a)(3b) (3b)2 (2a 3b)(2a 3b) (2a 3b)2 EXAMPLE 4 Factor:

If we assume y(0)= 1, y(1)= 4, y(2)= 8, y(3)= 13, we have four . d= 1. y(1)= a+ b+

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Untitled.notebook. January 10, 2008. Factor. 12. 8y3 + 27. Page 20. Untitled. .

x3 + y3 = (x + y)(x2 – xy +y2). x3 – y3 = (x – y) (x2 + xy +y2). Ex. 4x2 – 9 = (2x – 3)

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Solve by the substitution method 7x+3y -12 x 21-8y 3. . 27. The length of a

i) 27:64 (ii) 8y3 : 27x3 7. 7:4 8.4:5 9.^"^ 10.24,40 W.ab 12.x2- v2 a - b cx 13. — 14

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